# Question #d5f5d

$\text{1 molar NaOH}$ SPECIFIES a $40 \cdot g$ mass of $\text{NaOH}$ in enuff water to make $1 \cdot L$ of solution.....
And concentration $=$ $\text{Moles of NaOH"/"Volume of solution}$
$= \frac{\frac{40 \cdot g}{40.0 \cdot g \cdot m o {l}^{-} 1}}{1 \cdot L} = 1.0 \cdot m o l \cdot {L}^{-} 1$.