# What is the volume of 2*mol of an Ideal Gas at 0 ""^@C, and 1*atm?

Jul 21, 2017

$4.54 \cdot {10}^{- 2} {m}^{3}$

#### Explanation:

The ideal gas law says that, $p V = n R T$, where:
$p$ = pressure ($P a$)
$V$ = volume (${m}^{3}$)
$n$ = number of moles ($m o l$)
$R$ = gas constant, ($8.31 J$ ${K}^{- 1}$ $m o {l}^{- 1}$)
$T$ = temperature ($K$)

$1$ $a t m \approx 100000 P a$
${0}^{\circ} C \approx {273}^{\circ} K$

$V = \frac{n R T}{P} = \frac{2 \cdot 8.31 \cdot 273}{100000} = 0.0453726 {m}^{3} \approx 0.0454 {m}^{3} = 4.54 \cdot {10}^{- 2} {m}^{3}$