Question

What is the volume of `2*mol` of an Ideal Gas at `0` `""^@C`, and `1*atm`?

Answer 1

`4.54*10^(-2)m^3`

Explanation:

The ideal gas law says that, `pV=nRT`, where:
`p` = pressure (`Pa`)
`V` = volume (`m^3`)
`n` = number of moles (`mol`)
`R` = gas constant, (`8.31J` `K^(-1)` `mol^(-1)`)
`T` = temperature (`K`)

`1` `atm ~~ 100000Pa`
`0^circC ~~ 273^circK`

`V=(nRT)/P=(2*8.31*273)/100000=0.0453726m^3~~0.0454m^3=4.54*10^(-2)m^3`