# How many nitrate ions does a metal draft in to form a metal nitrate?

Well, suppose the metal forms a univalent cation, i.e. ${M}^{+}$...
Its nitrate salt drafts in the required numbers of moles of nitrate, $N {O}_{3}^{-}$, to achieve neutrality.
And so we could form $K N {O}_{3}$, or $N a N {O}_{3}$, or $C a {\left(N {O}_{3}\right)}_{2}$, or $F e {\left(N {O}_{3}\right)}_{3}$....