# Question #60265

At first you have to balance the reaction: $C {H}_{4} + 2 {O}_{2} = C {O}_{2} + 2 {H}_{2} O$
but this time doesn't change the ratio between methane and carbon dioxide that is 1:1. Since the molecular mass of methane is 16g/mol you have $\frac{246 g}{16 \left(\frac{g}{m} o l\right)} = 15 , 375$ mol of $C {H}_{4}$ and also of carbon dioxide