If #50*g# of aluminum is oxidized, what mass of alumina will be recovered?
We follow the stoichiometric equation........
And this 2 equiv of metal required 3/2 equivalents of dioxygen gas.
And since aluminium is CLEARLY the so-called limiting reagent in this reaction (since we know precisely how much mass of
And thus the mass of alumina is given by the product....
Look for videos on molar equivalence and stoichiometry on the web. Perhaps this one: