# Question 792b1

Jul 26, 2017

$\text{0.83 L}$

#### Explanation:

Molarity is all about the number of moles of solute and the volume of the solution expressed in liters, so start by using the 8molar mass* of calcium chloride to calculate the number of moles present in your sample.

212 color(red)(cancel(color(black)("g"))) * "1 mole CaCl"_2/(110.98color(red)(cancel(color(black)("g")))) = "1.91 moles CaCl"_2#

Now, you know that in order to have a $\text{2.3-M}$ solution of calcium chloride, you need to have $2.3$ moles of calcium chloride for every $\text{1 L}$ of solution.

Since solutions are homogeneous mixtures, i.e. they have the same composition throughout, you can use the molarity of the solution as a conversion factor to find the volume of solution that would contain $1.91$ moles of solute.

$1.91 \textcolor{red}{\cancel{\textcolor{b l a c k}{\text{moles CaCl"_2))) * overbrace("1 L solution"/(2.3color(red)(cancel(color(black)("moles CaCl"_2)))))^(color(blue)("= 2.3 M")) = color(darkgreen)(ul(color(black)("0.83 L solution}}}}$

The answer is rounded to two sig figs, the number of significant figures you have for the molarity of the solution.