# How many diastereomers can H_3C-CH=CH-CH(OH)CH_3 generate?

For ${H}_{3} C - C H = C H - C H \left(O H\right) - C {H}_{3}$, I count 4 diastereomers........
You gots ${H}_{3} C - C H = C H - C H \left(O H\right) - C {H}_{3}$, with 2 sites of dissymmetry, (i) the olefinic bond, which can of course be cis or trans depending on the geometry to methyl or alcoholic groups, and of course the asymmetric carbon,
${H}_{3} C - C H = C H - \stackrel{\cdot}{C} H \left(O H\right) - C {H}_{3}$.