Question #8e9bf
2 Answers
Jul 29, 2017
Explanation:
Assuming your question says
Steps
- First move all values with denominator
a-2 to the right side.
a/2=6/(a-2)+(6-3a)/(a-2) Simplify this.
a/2=(6+6-3a)/(a-2) → Simplify again →a/2=(12-3a)/(a-2) - Now find the common denominator to make the fractions equivalent.
(a(a-2))/(2(a-2))=(2(12-3a))/(2(a-2)) Simplify this.
(a^2-2)/(2a-4)=(24-6a)/(2a-4) We can now take out the denominator as both sides are equivalent. - Calculate to find
a : first, set up quadratic. Make one side 0.
a^2-2=24-6a
a^2-26+6a=0 reorder this
a^2+6a-26=0 - Solving the quadratic here
Answer
Jul 30, 2017
Explanation:
Assuming your question says
Steps
- First set all denominators equal; common denominator is
2(a-2)
\therefore\(a(a-2))/(2(a-2))-(2(6))/(a(a-2))=(6(2(a-2)))/(2(a-2))-(2(3a))/(2(a-2))
simplifying(a^2-2a)/(2a-4)-12/(2a-4)=(12a-24)/(2a-4)-(6a)/(2a-4) - Now take out the denominator since everything is equivalent...
(a^2-2a)-12=(12a-24)-6a
a^2-2a-12=6a-24 adding like terms on right side... - Make a quadratic (form
ax^2+bx+c ) to solve:
a^2-8a-12=0 moving all terms to left side...
solving here
Answer