What is the concentration of a #40*g# mass of sodium hydroxide dissolved in #250*mL# of water?

1 Answer
Jul 30, 2017

Answer:

Approx. #4*mol*L^-1#.......or #4.0*"normal"#

Explanation:

#[NaOH]=((40*g)/(40*g*mol^-1))/(250xx10^3*mLxx10^-3*L*mL^-1)=4.0*mol*L^-1#

This follows the normal means of calculation, #"concentration"="moles of solute"/"volume of solution"#, and thus get an answer in #mol*L^-1#.

We assume no volume change on dissolution.

And under these circumstances, where the solute causes no further water hydrolysis, #"molarity "-=" normality"#...........