Question #f4097

1 Answer
Aug 2, 2017

Answer:

#"pressure" = 45.9# #"psi"#

Explanation:

We're asked to find the final pressure of the gas, given its initial pressure, initial temperature, and final temperature.

We can use Gay-Lussac's law for this problem, which is

#ul((P_1)/(T_1) = (P_2)/(T_2))color(white)(aa)# (constant volume and quantity)

where

  • #P_1# is the initial pressure

  • #P_2# is the final pressure (what we're trying to find)

  • #T_1# is the initial absolute temperature (in Kelvin)

  • #T_2# is the final absolute temperature (in Kelvin)

We have:

  • #P_1 = 32.6# #"psi"#

  • #P_2 = ?#

  • #T_1 = 735# #"K"#

  • #T_2 = 1035# #"K"#

Let's rearrange the above equation to solve for the final pressure, #P_2#:

#P_2 = (P_1T_2)/(T_1)#

Plugging in known values:

#P_2 = ((32.6color(white)(l)"psi")(1035cancel("K")))/(735cancel("K")) = color(red)(ulbar(|stackrel(" ")(" "45.9color(white)(l)"psi"" ")|)#