What is the perimeter of a rectangle with a width of #10 3/5# and a length of #14 18/25#?

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Answer 1 · 2017-08-03T03:14:31

See a solution process below:

The formula for the perimeter of a rectangle is:

#p = 2(w + l)# Where

#p# is the perimeter, what we are solving for.

#w# is the width of the rectangle.

#l# is the length of the rectangle.

Substituting gives:

#p = 2(10 3/5 + 14 18/25)#

First, convert the mixed numbers to improper fractions:

#p = 2([10 + 3/5] + [14 + 18/25])#

#p = 2([(5/5 xx 10) + 3/5] + [(25/25 xx 14) + 18/25])#

#p = 2([50/5 + 3/5] + [350/25 + 18/25])#

#p = 2(53/5 + 368/25)#

Next, put the fraction on the left over a common denominator by multiplying by the appropriate form of #1#:

#p = 2([5/5 xx 53/5] + 368/25)#

#p = 2([(5 xx 53)/(5 xx 5)] + 368/25)#

#p = 2(265/25 + 368/25)#

Then, add the fractions and multiply by #2#:

#p = 2(633/25)#

#p = 1266/25#

Now, if necessary, convert the improper fraction to a mixed number:

#p = (1250 + 16)/25#

#p = 1250/25 + 16/25#

#p = 50 + 16/25#

#p = 50 16/25#