Question #73baa

1 Answer
Jan 22, 2018

#sin t = - 3/5#

Explanation:

Use trig identity:
#sin^2 x = 1/(1 + cot^2 x)#
In this case:
#sin^2 t = 1/(1 + 16/9) = 1/(25/9) = 9/25#
#sin t = +- 3/5#
Because 180 < t < 270, therefor, sin t is negative:
#sin t = - 3/5#