# What is the new pressure of a gas under 1112*"psi" with a volume of 6.53*L that is expanded to a volume of 12.45*L?

Well ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$ according to old $\text{Boyle's Law}$.
Given the proportionality, we could use any units of pressure, and volume, i.e. $\text{psi}$, or $\text{pints}$, or $\text{gallons}$ as Boyle, working in the 17th century, undoubtedly did.
And so P_2=(P_1V_1)/V_2=(1112*"psi"xx6.53*L)/(12.45*L)=??"psi"