What is the new pressure of a gas under 1112*"psi" with a volume of 6.53*L that is expanded to a volume of 12.45*L?

1 Answer
Aug 4, 2017

Well P_1V_1=P_2V_2 according to old "Boyle's Law".

Explanation:

Given the proportionality, we could use any units of pressure, and volume, i.e. "psi", or "pints", or "gallons" as Boyle, working in the 17th century, undoubtedly did.

And so P_2=(P_1V_1)/V_2=(1112*"psi"xx6.53*L)/(12.45*L)=??"psi"