# Question 50579

Aug 4, 2017

$\text{V} = 250$ $\text{mL}$

#### Explanation:

The formula for finding the molarity of a solute is "Molarity" = frac("moles of solute")("volume of solution").

We are already provided with the molarity, but we still need to find the number of moles of solute:

$R i g h t a r r o w n = \frac{m}{M}$

Rightarrow n = frac(6.94 " g")((40.08 + 2 times 35.45) " g mol"^(- 1))

$R i g h t a r r o w n = \frac{6.94}{110.98 {\text{ mol}}^{- 1}}$

$R i g h t a r r o w n = 0.0625$ $\text{mol}$

Then, let's substitute all relevant values into the formula for molarity:

Rightarrow 0.250 "M" = frac(0.0625 " mol")("volume of solution")

Rightarrow 0.250 "mol L"^(- 1) = frac(0.0625 " mol")("volume of solution")

Rightarrow "Volume of solution" = frac(0.0625 " mol")(0.250 " mol L"^(- 1))#

$R i g h t a r r o w \text{Volume of solution} = 0.250$ $\text{L}$

$\therefore \text{Volume of solution} = 250$ $\text{mL}$

Therefore, the volume of the calcium chloride solution is $250$ $\text{mL}$.