How do you solve #abs(2x+3)+4=5x#?

1 Answer
Aug 5, 2017

#x=1/7,7/3#

Refer to the explanation for the process.

Explanation:

Solve:

#abs(2x+3)+4=5x#

Since #absa=a# and #abs(-a)=a#, there is both a positive and negative component to the equation, therefore you will have two equations to solve.

First Equation: (2x+3) is Positive

#2x+3+4=5x#

Subtract #2x# from both sides.

#3+4=5x-2x#

Simplify.

#7=3x#

Divide both sides by #3#.

#7/3=x#

Switch sides.

#x=7/3#

Second Equation: (2+3) is Negative

#-(2x+3)+4=5x#

Simplify.

#-2x-3+4=5x#

Add #2x# to both sides.

#-3+4=5x+2x#

Simplify.

#1=7x#

Divide both sides by #7#.

#1/7=x#

Switch sides.

#x=1/7#

Therefore:

#x=1/7,7/3#