Question #55516

1 Answer
Aug 8, 2017

0.4 M

Explanation:

#text(Molarity) = text(Weight of solute)/text(Gram molecular weight of solute) xx 1000 / (text(Volume of solution in ml))#

#text(Molarity) = text(Weight of NaOH)/text(Gram molecular weight of NaOH) xx 1000 / (text(Volume of solution in ml))#

#text(Molarity) = 4/40 xx 1000/(250)#

#text(Molarity) = 0.4 text(M)#