Question

Question #c1032

Answer 1

`"range" = 16` `"units"`

Explanation:

We're asked to find the horizontal range of a projectile, given its trajectory equation.

Well, when the projectile lands again, its height (`y`) will be zero, so what we can do is find the zeros of this function:

`y = 12x - 3/4x^2`

Since `y = 0`:

`0 = x(12-3/4x)`

`0 = 12-3/4x`

`color(red)(ulbar(|stackrel(" ")(" "x = 16color(white)(l)"units"" ")|)`

The horizontal range of this projectile is thus `16` `"units"` (no units for distance were given).