# Question c1032

##### 1 Answer
Aug 11, 2017

$\text{range} = 16$ $\text{units}$

#### Explanation:

We're asked to find the horizontal range of a projectile, given its trajectory equation.

Well, when the projectile lands again, its height ($y$) will be zero, so what we can do is find the zeros of this function:

$y = 12 x - \frac{3}{4} {x}^{2}$

Since $y = 0$:

$0 = x \left(12 - \frac{3}{4} x\right)$

$0 = 12 - \frac{3}{4} x$

color(red)(ulbar(|stackrel(" ")(" "x = 16color(white)(l)"units"" ")|)#

The horizontal range of this projectile is thus $16$ $\text{units}$ (no units for distance were given).