# Question #c1032

##### 1 Answer

Aug 11, 2017

#### Explanation:

We're asked to find the **horizontal range** of a projectile, given its trajectory equation.

Well, when the projectile lands again, its height (**zeros** of this function:

#y = 12x - 3/4x^2#

Since

#0 = x(12-3/4x)#

#0 = 12-3/4x#

#color(red)(ulbar(|stackrel(" ")(" "x = 16color(white)(l)"units"" ")|)#

The horizontal range of this projectile is thus