# What is the molar concentration of "38% w/w HCl"?

Aug 12, 2017

$\text{Concentration HCl} = 12.7 \cdot m o l \cdot {L}^{-} 1$

#### Explanation:

How did I get that figure? Well we need a value for the density of $H C l$; this site reports that the density of 38% $H C l$ is $\rho = 1.189 \cdot g \cdot m L$. Now we need this value if we are to approach the question......

$\text{Concentration"="Molarity"="Moles of solute (mol)"/"Volume of solution (L)}$

And thus.....$\text{molarity}$ using a volume of $1 \cdot m L$....

=((38%xx1.189*g*mL^-1xx1*mL)/(35.45*g*mol^-1))/(1xx10^-3*L)=12.7*mol*L^-1.