Question #0386f

1 Answer
sjc
Feb 16, 2018

#(dy)/(dx)=-2/(sqrt((3-2x)^2-1))#

Explanation:

#y=cosh^(-1)(3-2x)#

#=>coshy=3-2x#

#d/(dx)(coshy)=d/(dx)(3-2x)#

#(dy)/(dx)sinhy=-2#

#(dy)/(dx)=-2/sinhy#

#cosh^2y-sinh^2y=1#

#:.sinh^2y=cosh^2y-1#

#(dy)/(dx)=-2/(sqrt((3-2x)^2-1))#

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