Question #ca241

1 Answer
Aug 17, 2017

Answer:

The final temperature of the water is 39.5 °C.

Explanation:

The formula for the heat #q# gained or lost by a substance is

#color(blue)(bar(ul(|color(white)(a/a)q = mcΔTcolor(white)(a/a)|)))" "#

where

#m# is the mass of the substance.
#c# is its specific heat capacity.
#ΔT = T_"f" - T_"i"# is the change in temperature.

In this problem,

#q = "5.78 kJ" = "5780 J"#

#m = "328 g"#

#C = "4.18 J°C"^"-1""g"^"-1"#

#ΔT = T_"f"color(white)(l) "- 35.3 °C"#

#q = 328 color(red)(cancel(color(black)("g"))) × 4.18 color(red)(cancel(color(black)("J")))"°C"^"-1"color(red)(cancel(color(black)("g"^"-1"))) × ΔT = 5780 color(red)(cancel(color(black)("J")))#

#1371ΔT "°C"^"-1" = 5780#

#ΔT = 5780/(1371 "°C"^"-1") = "4.22 °C"#

#ΔT = T_"f"color(white)(l) "- 35.3 °C" = "4.22 °C"#

#T_"f" = "35.3 °C + 4.22 °C" = "39.5 °C"#