Question #bd476

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Answer 1 · 2017-08-17T23:08:29

$tan(x)=+-1$

$sec(x)^2= tan(x)^2+1$

derived from $sin(x)^2+cos(x)^2=1$ divide all by cos(x)^2

$2tan(x)^2-(tan(x)^2+1)$

$2tan(x)^2-tan(x)^2-1=0$

$tan(x)^2=1$

$tan(x)=+-1$

$tan(x)$ can be equal to

${ − 45 ∘ , 45 ∘ , 135 ∘ , 225 ∘ } .$