Question #2db1c

1 Answer
Aug 20, 2017

but-1-ene: #CH_2=C(H)-CH_2-CH_3#
but-2-ene: #CH_3 - C(H) = C(H) - CH_3#

When you add chlorine to an alkene it undergoes an addition reaction to form a haloalkane. The double bond is broken and the Cl's go on to these new bonds.
But-1-ene + #Cl_2# can form 1,2-dichlorobutane
But-2-ene + #Cl_2# can form 2,3-dichlorobutane

These are different because of where the double bond is in the molecules. The Cl groups go onto the spare space on the C atom that previously was double bonded.