How would we identify #Bu^(t)CO_2H# by its IR spectrum?

1 Answer
Aug 20, 2017

You have probably got #D#.

Explanation:

Now I cannot even see the scale of your IR spectrum, but there is a VERY broad peak around about #3000*cm^-1#, which is consistent with the presence of #-O-H# bonds. Further, there is (I think) a strong peak at #1650-1750*cm^-1# that is probably due to #C=O#.

So #C# and #B# are non-starters, and the choice is between #A# and #D#. Because #A# is an alcohol, and DOES not possess a carbonyl, this choice is contraindicated, and we choose #D#.

IR spectroscopy is a very poor discriminant of organic structure. If you really want to identify the stuff as #Bu^tC(=O)OH# you would have to make a few derivatives and take melting points.