# How to write and balance the equation for the reaction: sodium fluoride plus copper(II) nitrate produces sodium nitrate plus copper(II) fluoride?

Aug 20, 2017

Refer to the explanation.

#### Explanation:

You need to determine the formulas first.

sodium fluoride: $\text{NaF}$

copper(II) nitrate: ${\text{Cu(NO"_3)}}_{2}$

sodium nitrate: ${\text{NaNO}}_{3}$

copper(II) fluoride: ${\text{CuF}}_{2}$

$\text{NaF + Cu(NO"_3)_2}$$\rightarrow$${\text{NaNO"_3 + "CuF}}_{2}$

All of these compounds are ionic. If we look first at the polyatomic ion ${\text{NO"_3}}^{-}$ as a whole, we can see that there are two of them on the lefthand side and one on the righthand side. So you need to place a coefficient of $2$ in front of $\text{NaNO"_3}$. That will cause the $\text{NaF}$ to be unbalanced, so you need to place a coefficient of $2$ in front of $\text{NaF}$. This will balance the fluoride ions, and you're done.

$\text{2NaF + Cu(NO"_3)_2}$$\rightarrow$${\text{2NaNO"_3 + "CuF}}_{2}$