# Question #1286b

Aug 20, 2017

The test material is incorrect.

#### Explanation:

First convert 2.0 grams of $N {O}_{2}$ to moles.

$1 N = 1 \times 14 = 14$
$2 O - 2 \times 16 = 32$ adding them gives

$14 + 32 = 46$ grams /mole

$\frac{2.0 g}{46 \frac{g}{m}} = 0.043$ moles

Next change moles nitrogen oxide to moles ozone.
There is a one to one ratio of moles nitrogen oxide to ozone. so

0.043 moles $N {O}_{2}$ = 0.043 moles ${O}_{3}$s

Third change mole Ozone to grams.

${O}_{3} = 3 \times O = 3 \times 16 = 48$ grams/mole

$0.043 \times 48 \frac{g}{m} = 2.1$ grams ozone.

Your answer is completely reasonable except you have too many significant digits. The problem with 2.0 grams of nitrogen oxide has only two significant digits so your answer should have only two significant digits.

None of the answers given are correct, or even close to correct.