Question #00c6f

Aug 22, 2017

There are 1.1 g of ${\text{NH}}_{3}$ in the solution.

Explanation:

Step 1. Calculate the moles of ${\text{NH}}_{3}$

${\text{Moles of NH"_3 = 0.085 color(red)(cancel(color(black)("L NH"_3))) × "0.75 mol NH"_3/(1 color(red)(cancel(color(black)("L NH"_3)))) = "0.0638 mol NH}}_{3}$

Step 2. Calculate the mass of ${\text{NH}}_{3}$

${\text{Mass of NH"_3 = 0.0638 color(red)(cancel(color(black)("mol NH"_3))) × "17.03 g NH"_3/(1 color(red)(cancel(color(black)("mol NH"_3)))) = "1.1 g NH}}_{3}$