What is the logarithm of #100# divided by #25# ?

1 Answer
Aug 22, 2017

#log(100/25) = 2log(2) ~~ 0.60206#

#log(100)/25 = 2/25 = 0.08#

Explanation:

A good approximation is:

#log(2) ~~ 0.30103#

So we find:

#log(100/25) = log(4) = log(2*2) = 2log(2) ~~ 0.60206#

If instead you intended #log(100)/25# then we find:

#log(100)/25 = log(10^2)/25 = 2/25 = 8/100 = 0.08#