# What is the heat absorbed by "27 g" of water that increases in temperature by 58^@ "C"? Assume c = "4.184 J/g"^@ "C" for water in this temperature range.

Aug 23, 2017

$Q = \text{6600 Joules}$

#### Explanation:

The heat $Q$ for a given mass $m$ of water with specific heat capacity $c = \text{4.184 J/g"^@ "C}$ that increases in temperature by ${58}^{\circ} \text{C}$ is given by:

$Q = m c \Delta T$

= ("27 g") cdot ("4.184 J"//"g"^@"C")(58^@"C") = "6552 J"

$\approx$ $\text{6600 J}$