What mass of lithium carbonate will result, if #87.2*g# of #LiOH# is treated with excess carbon dioxide?

1 Answer
Aug 23, 2017

Answer:

Approx. #130*g# of #"lithium carbonate"# will result.....

Explanation:

We need a stoichiometrically balanced equation.....

#CO_2(aq) + 2LiOH(aq) rarr Li_2CO_3(s) + H_2O(l)#

Is this balanced?

And then we work out the molar equivalence.....

#"Moles of lithium hydroxide"=(87.2*g)/(23.95*g*mol^-1)=3.64*mol.#

And given excess carbon dioxide gas, we gets a mass of #(3.64*mol)/2xx73.89*g*mol^-1=134.5*g# WITH RESPECT TO lithium carbonate.