# What mass of lithium carbonate will result, if 87.2*g of LiOH is treated with excess carbon dioxide?

Aug 23, 2017

Approx. $130 \cdot g$ of $\text{lithium carbonate}$ will result.....

#### Explanation:

We need a stoichiometrically balanced equation.....

$C {O}_{2} \left(a q\right) + 2 L i O H \left(a q\right) \rightarrow L {i}_{2} C {O}_{3} \left(s\right) + {H}_{2} O \left(l\right)$

Is this balanced?

And then we work out the molar equivalence.....

$\text{Moles of lithium hydroxide} = \frac{87.2 \cdot g}{23.95 \cdot g \cdot m o {l}^{-} 1} = 3.64 \cdot m o l .$

And given excess carbon dioxide gas, we gets a mass of $\frac{3.64 \cdot m o l}{2} \times 73.89 \cdot g \cdot m o {l}^{-} 1 = 134.5 \cdot g$ WITH RESPECT TO lithium carbonate.