# How do you evaluate #lim_(x-> 0) tanx/x#?

##### 2 Answers

Since

#L = lim_(x->0) (sec^2x)/1#

#L = lim_(x->0) sec^2x#

#L = sec^2(0)#

#L = 1/cos^2(0)#

#L = 1#

If we check the graph of the function

Hopefully this helps!

Aug 25, 2017

Please see below.

#### Explanation:

So,

# = lim_(xrarro) sinx/x * lim_(xrarro)1/cosx#

# = 1*1/1 = 1#