Question #b5b58

1 Answer
anor277
Aug 28, 2017

Surely it is #"option B"#

Explanation:

You gots #A. H_2C=CH-stackrel(+)CHCH_3#, where the carbocation is resonance stabilized, and #C#, a tertiary carbocation, and #D#, a benzyl carbocation...#C_6H_5stackrel(+)CH-CH_3#.

All are stabilized with respect to #B#, a #2^@# carbocation, #H_3C-stackrel(+)CHCH_2CH_3#, and thus this carbocation should be the LEAST stable, and have the shortest lifetime.

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