# What is the concentration in "ppm" if 18.5*g of solute are dissolved in a 125*L volume?

Well $1 \cdot \text{ppm}$ $=$ $1 \cdot m g \cdot {L}^{-} 1$.......
And so we set up the quotient, $\text{milligrams of solute"/"litres of water}$
$= \frac{18.5 \cdot g \times {10}^{3} \cdot m g \cdot {g}^{-} 1}{125000 \cdot g \times {10}^{-} 3 \cdot L \cdot {g}^{-} 1} = 148.0 \cdot \text{ppm}$