Question

What is the concentration of a `1*mL` volume of a solution of `37%` `HCl` `(rho=1.18*g*mL^-1)` that is diluted to `3.50*mL`?

Answer 1

You really have not specified the boundary conditions of this problem correctly........

Explanation:

Now, I ASSUME that you have diluted a `1*mL` volume of `37%` `"w/w"` hydrochloric solution to `3.5*mL`. In order to calculate this problem you need the density of the conc. acid, which is `rho=1.18*g*mL^-1`. These data SHOULD have been included with the question.

So we want `"moles of solute"/"volume of solution"`

`=((1*mLxx1.18*g*mL^-1xx37%)/(36.46*g*mol^-1))/(3.5*cancel(mL)xx10^-3*L*cancel(mL^-1))=3.4*mol*L^-1`