What is the concentration of a #1*mL# volume of a solution of #37%# #HCl# #(rho=1.18*g*mL^-1)# that is diluted to #3.50*mL#?

1 Answer
Aug 30, 2017

Answer:

You really have not specified the boundary conditions of this problem correctly........

Explanation:

Now, I ASSUME that you have diluted a #1*mL# volume of #37%# #"w/w"# hydrochloric solution to #3.5*mL#. In order to calculate this problem you need the density of the conc. acid, which is #rho=1.18*g*mL^-1#. These data SHOULD have been included with the question.

So we want #"moles of solute"/"volume of solution"#

#=((1*mLxx1.18*g*mL^-1xx37%)/(36.46*g*mol^-1))/(3.5*cancel(mL)xx10^-3*L*cancel(mL^-1))=3.4*mol*L^-1#