What is the #"molality"# of a solution composed of #684*g# of sucrose dissolved in a mass of #1000*g# of water?

1 Answer
Sep 3, 2017

Answer:

#"Molality"="Moles of solute"/"Kilograms of solvent.."#

Explanation:

And so, we take the quotient......

#((684*g)/(342.3*g*mol^-1))/(1.000*kg)=2.00*mol*kg^-1#.

We would need the density of the solution to convert this to the #"molarity"#, which is specified by the quotient, #"molarity"="moles of solute"/"volume of solution"#. The values would not be too much different.