A #4.60*L# volume of gas at #845*mm*Hg# pressure is expanded such that the new pressure is #368*mm*Hg#. To what volume does it expand?
2 Answers
Answer:
A measurement of
Explanation:
See this old question.......
To solve this question we would use.....
Answer:
Explanation:
NOTE: Ideally, measurements of pressures greater than
We're asked to find the volume necessary for a gas system to exert a pressure of
To do this, we can use the pressurevolume relationship of gases illustrated by Boyle's law:
#ulbar(stackrel(" ")(" "P_2V_1 = P_2V_2" "))" "# (constant temperature and quantity)
where

#P_1# and#P_2# are the initial and final pressures of the gas, respectively 
#V_1# and#V_2# are the inital and final volumes of the gas, respectively
We know:

#P_1 = 845# #"mm Hg"# 
#V_1 = 4.60# #"L"# 
#P_2 = 368# #"mm Hg"# 
#V_2 = ?#
Let's rearrange the equation to solve for the final volume,
#V_2 = (P_1V_1)/(P_2)#
Plugging in known values:
#color(red)(V_2) = ((845cancel("mm Hg"))(4.60color(white)(l)"L"))/(368cancel("mm Hg")) = color(red)(ulbar(stackrel(" ")(" "10.6color(white)(l)"L"" "))#