# How would the volume if a gas in a piston under 14*"bar" pressure with a volume of 312*mL, were reduced in pressure to 7*"bar" pressure?

Sep 4, 2017

Would it not be around $7 \cdot \text{bar}$.........?

#### Explanation:

Old Boyle's Law holds that given constant temperature, and for a given amount of gas.....$P \propto \frac{1}{V}$........

Else, $P V = k$, and thus solving for $k$ at different pressures and volumes......

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

And so......P_2=(P_1V_1)/V_2=(14*"bar"xx312*mL)/(652*mL)=??*"bar".