How would the volume if a gas in a piston under #14*"bar"# pressure with a volume of #312*mL#, were reduced in pressure to #7*"bar"# pressure?

1 Answer
Sep 4, 2017

Answer:

Would it not be around #7*"bar"#.........?

Explanation:

Old Boyle's Law holds that given constant temperature, and for a given amount of gas.....#Pprop1/V#........

Else, #PV=k#, and thus solving for #k# at different pressures and volumes......

#P_1V_1=P_2V_2#

And so......#P_2=(P_1V_1)/V_2=(14*"bar"xx312*mL)/(652*mL)=??*"bar"#.