Question

Question #482bb

Answer 1

See a solution process below:

Explanation:

If we want to find the cost per pound we can write and solve:

`c/(1"lb") = ($7.96)/(5"lb")`

`color(red)(1"lb") xx c/(1"lb") = color(red)(1"lb") xx ($7.96)/(5"lb")`

`cancel(color(red)(1"lb")) xx c/color(red)(cancel(color(black)(1"lb"))) = color(red)(1color(black)(cancel(color(red)("lb")))) xx ($7.96)/(5color(red)(cancel(color(black)("lb"))))`

`c = ($7.96)/5`

`c = $1.592`

The rate is `$1.59` per pound.