# Question #f3e56

Sep 9, 2017

Turn it into a quadratic equation...

#### Explanation:

...which I don't think is too tough:

Multiply out the left side:

${x}^{2} - 2 x + 1 = 4 x - 5$

Subtract 4x from both sides:

${x}^{2} - 6 x + 1 = - 5$

${x}^{2} - 6 x + 6 = 0$

So now it's in the classic quadratic equation form ax^2 +bx + c = 0,
where a = 1, b = -6, and c = 6.

And I'll bet you've seen these solved before...

the roots here are given by the familiar formula:

$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

with roots 4.73 and 1.27 (rounded to 3 digits)

GOOD LUCK!