Question #a317c
1 Answer
Explanation:
The idea here is that when the volume of the gas and the number of moles of gas present in your sample remain constant, increasing the temperature of the gas will cause its pressure to increase as well

Mathematically, this can be written like this
color(blue)(ul(color(black)(P_1/T_1 = P_2/T_2)))
Here
P_1 ,T_1 are the pressure and absolute temperature of the gas at an initial stateP_2 andT_2 are the pressure and absolute temperature of the gas at final state
In your case, the temperature of the gas is increasing, so you should expect to find
P_2 > "0.96 atm"
Rearrange the equation to solve for
P_1/T_1 = P_2/T_2 implies P_2 = T_2/T_1 * P_1
Plug in your values to find
P_2 = (684 color(red)(cancel(color(black)("K"))))/(478color(red)(cancel(color(black)("K")))) * "0.96 atm" = color(darkgreen)(ul(color(black)("1.4 atm")))
The answer is rounded to two sig figs, the number of sig figs you have for the initial pressure of the gas.