Question #a317c

1 Answer
Sep 6, 2017

"1.4 atm"1.4 atm

Explanation:

The idea here is that when the volume of the gas and the number of moles of gas present in your sample remain constant, increasing the temperature of the gas will cause its pressure to increase as well -> think Gay Lussac's Law here.

![http://chemistryhungergames.weebly.com/district-6http://---gases.html](https://useruploads.socratic.org/e6s9vqUaS72ibx0Od29i_3724087.jpg)

Mathematically, this can be written like this

color(blue)(ul(color(black)(P_1/T_1 = P_2/T_2)))

Here

  • P_1, T_1 are the pressure and absolute temperature of the gas at an initial state
  • P_2 and T_2 are the pressure and absolute temperature of the gas at final state

In your case, the temperature of the gas is increasing, so you should expect to find

P_2 > "0.96 atm"

Rearrange the equation to solve for P_2

P_1/T_1 = P_2/T_2 implies P_2 = T_2/T_1 * P_1

Plug in your values to find

P_2 = (684 color(red)(cancel(color(black)("K"))))/(478color(red)(cancel(color(black)("K")))) * "0.96 atm" = color(darkgreen)(ul(color(black)("1.4 atm")))

The answer is rounded to two sig figs, the number of sig figs you have for the initial pressure of the gas.