# Question #5c4d2

Sep 6, 2017

$\frac{\mathrm{dy}}{\mathrm{dx}} = - \left(\frac{8}{9 {x}^{4}} + 9 \sin \left(x\right)\right)$

#### Explanation:

$y = \frac{8}{3} ^ 3 {x}^{- 3} + 9 \cos \left(x\right)$

The first term just requires a simple application of the power rule, while the second is a standard derivative:

$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{8}{3} ^ 3 \left(- 3\right) {x}^{- 4} - 9 \sin \left(x\right)$

$\frac{\mathrm{dy}}{\mathrm{dx}} = - \left(\frac{8}{9 {x}^{4}} + 9 \sin \left(x\right)\right)$