# Question #1e5b9

##### 1 Answer

Relative velocity of projectile w.r.t plane=Actual velocity of projectile-velocity of plane

So,Actual velocity of projectile=

Let's,consider that the projectile will touch the ground after time t,

So with in this time,along X axis if it travels a distance of s from its point of projection,we can say

And along Y axis,

Vertical height of plane above the ground = 800 =

Eliminating t from both the equations we get,

800 =

Or, s= 5551.56 meters

So at that time along x axis its velocity will be 438.89 m/sec

Along Y axis we can find it using equation

So,v= 126.5 m/sec

Hence net velocity with which it will hit the ground will be

Or, 456.75 m/sec