How many atoms are there in a #58.7*g# mass of #"ammonium nitrite"#?

1 Answer
anor277
Sep 10, 2017

Well, there are #(58.7*g)/(64.06*g*mol^-1)=0.916*mol# with respect to #"ammonium nitrite"#.....we get approx. #42xx10^23# individual atoms.

Explanation:

And so..................

#"no. of atoms"="moles of ammonium nitrite"xx"7 atoms mol"^-1xxN_A#

where #N_A=6.022xx10^23........#

And so we gots #7xx6.022xx10^23*mol^-1xx0.916*mol=??#

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