Question #cab94

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Answer 1 · 2017-12-28T17:55:37

#DeltaABC# is isosceles having, #A=B#.

We use the Sine Rule for #DeltaABC# which states,

#a/sinA=b/sinB=c/sinC=2R, (R" the circumradius)"#.

#:. acotA=bcotB,#

#rArr 2RsinA*cosA/sinA=2RsinB*cosB/sinB, i.e., #

#cosA=cosB#.

# :. A=B, or, A=2pi-B#.

In #DeltaABC," only "A=B# is possible.

Clearly, the #Delta# is isosceles having, #A=B#.