What are the carboxylic acid isomers of #C_4H_8O_2#...?

1 Answer
anor277
Sep 10, 2017

Well, we got linear #"butyric acid"#, #H_3C-CH_2CH_2CO_2H#...

Explanation:

And we gots branched #"isobutyric acid"#, #H_3C-CH(CH_3)CO_2H#.

Which isomer has the higher boiling point?.....My money is on the former....Why should I make this choice.

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