# What mass of salt is contained in a 200*mL volume of solution that is 0.10*mol*L^-1 with respect to KCl(aq)?

Sep 11, 2017

Approx. $1.5 \cdot g$ with respect to the salt.....

#### Explanation:

By definition, $\text{concentration"="quantity of stuff (mole or grams)"/"volume of solution}$

We have $200 \cdot m L$ volume of $K C l \left(a q\right)$ that is $0.1 \cdot m o l \cdot {L}^{-} 1$ with respect to potassium chloride.....

And so we take the product, and remember that $1 \cdot m L \equiv 1 \times {10}^{-} 3 \cdot L$, and so.....

$200 \cdot \cancel{m L} \times 0.10 \cdot m o l \cdot \cancel{{L}^{-} 1} \times {10}^{-} 3 \cdot \cancel{L} \cdot \cancel{m {L}^{-} 1} =$

$= 20.0 \times {10}^{-} 3 \cdot m o l$

But potassium chloride has a molar mass of $74.55 \cdot g \cdot m o {l}^{-} 1$

And so we got a mass of.....

20.0xx10^-3*molxx74.55*g*mol^-1=??*g