# What is the density of a solution composed of 189*mL of water, and 54*g of salt?

Sep 11, 2017

Well, clearly, the masses are additive.....

#### Explanation:

And given that water has ${\rho}_{\text{density}} = 1.0 \cdot g \cdot m {L}^{-} 1$, we have a mass of (i) $189 \cdot m L \times 1.0 \cdot g \cdot m {L}^{-} 1 = 189 \cdot g$ with respect to water, and $54 \cdot g$ with respect to salt, we gots....

$\left(54 + 189\right) \cdot g = 243 \cdot g$ in total.

Given that the volume of the liquid would change marginally upon dissolution of the salt, can you tell us the density of the solution?

Remember, ${\rho}_{\text{density"="Mass of solution"/"Volume of solution}}$, the which would give us an answer in $g \cdot m {L}^{-} 1$.