# Question #5155e

Sep 12, 2017

$\left\{- \frac{a}{2} , a , 2 b\right\}$

#### Explanation:

We have: $5 \left(x - a\right) \left(2 b - x\right) \left(2 x + a\right) = 0$

Dividing through by $5$:

$R i g h t a r r o w \left(x - a\right) \left(2 b - x\right) \left(2 x + a\right) = 0$

Using the null factor law:

$R i g h t a r r o w x - a = 0 \therefore x = a$

$\mathmr{and}$

$R i g h t a r r o w 2 b - x = 0 R i g h t a r r o w 2 b = x \therefore x = 2 b$

$\mathmr{and}$

$R i g h t a r r o w 2 x + a = 0 R i g h t a r r o w 2 x = - a \therefore x = - \frac{a}{2}$

Therefore, the solution set to the equation is $\left\{- \frac{a}{2} , a , 2 b\right\}$.