How many oxygen molecules are needed to make a #3.43*g# mass of #SO_2#?

1 Answer
Sep 12, 2017

Answer:

Approx. #6.4xx10^22# dioxygens......

Explanation:

We need a stoichiometric equation....

#S(s) + O_2(g) rarr SO_2(g)#, and I have ASSUMED combustion to give #SO_2# (#SO_3# is a little trickier!).

And thus there are equimolar quantities of dioxygen and sulfur.

#"Moles of sulfur"=(3.43*g)/(32.06*g*mol^-1)=0.107*mol#.

And thus we need #0.107*mol# dioxygen, and this represents a number of #0.107*molxx6.022xx10^23*mol^-1=6.44xx10^22# oxygen MOLECULES.....