A sucrose solution has $ρ = 1.85 \cdot g \cdot m L^{- 1}$ $rho=1.85gmL^-1$ , and a concentration of $1.8% w/w$ $"1.8% w/w"$ . What is its concentration?

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A sucrose solution has $ρ = 1.85 \cdot g \cdot m L^{- 1}$ $rho=1.85gmL^-1$ , and a concentration of $1.8% w/w$ $"1.8% w/w"$ . What is its concentration?

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Answer 1 · 2017-12-23T15:43:38

Are you sure these data are kosher?

Explanation:

$1.8 %$ $1.8%$ $w/w$ $"w/w"$ is not a very concentrated solution. Would you recheck the question? $ρ_{solution}$ $rho_"solution"$ would be over $1 \cdot g \cdot m L^{- 1}$ $1*g*mL^-1$ , but would not approach $2 \cdot g \cdot m L^{- 1}$ $2*g*mL^-1$ .

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A sucrose solution has $ρ = 1.85 \cdot g \cdot m L^{- 1}$ $rho=1.85gmL^-1$ , and a concentration of $1.8% w/w$ $"1.8% w/w"$ . What is its concentration?

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Explanation:

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A sucrose solution has rho=1.85*g*mL^-1ρ=1.85⋅g⋅mL−1rho=1.85*g*mL^-1, and a concentration of "1.8% w/w"1.8% w/w"1.8% w/w". What is its concentration?

1 Answer

Explanation:

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A sucrose solution has $ρ = 1.85 \cdot g \cdot m L^{- 1}$ $rho=1.85gmL^-1$ , and a concentration of $1.8% w/w$ $"1.8% w/w"$ . What is its concentration?