# 35.18*g of potassium nitrate is dissolved in enough water to make 23.41*mL solution. What is [KNO_3]?

Sep 21, 2017

You could have asked this question more clearly.....

#### Explanation:

Generally, we want solubility in terms of $m o l \cdot {L}^{-} 1$....i.e.

$\text{Moles of solute"/"Volume of solution}$

And here we got (I think)....

$\frac{\frac{35.18 \cdot g}{101.10 \cdot g \cdot m o {l}^{-} 1}}{23.41 \cdot m L \times {10}^{-} 3 \cdot L \cdot m {L}^{-} 1} = 14.9 \cdot m o l \cdot {L}^{-} 1$

Potassium nitrate is exceptionally soluble in water, and here I don't think you even have a saturated solution. What does $\text{saturated}$ mean in this context?